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JEE MAIN_2026_
210126_S1
Question
80 mL of a hydrocarbon on mixing with 264 mL of oxygen in a closed U-tube undergoes complete combustion. The residual gases after cooling to 273 K occupy 224 mL . When the system is treated with KOH solution, the volume decreases to 64 mL . The formula of the hydrocarbon is:
Select the correct option:
A
$\mathrm{C}_2 \mathrm{H}_4$
B
$\mathrm{C}_4 \mathrm{H}_{10}$
C
$\mathrm{C}_2 \mathrm{H}_2$
D
$\mathrm{C}_2 \mathrm{H}_6$
✓ Correct! Well done.
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Solution
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Question Tags
JEE Main
Chemistry
Medium
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