The ratio of mass percentage $(\mathrm{w} / \mathrm{w})$ of $\mathrm{C}: \mathrm{H}$ in a hydrocarbon is $12: 1$. It has two carbon atoms. The weight (in g ) of $\mathrm{CO}_2(\mathrm{~g})$ formed when 3.38 g of this hydrocarbon is completely burnt in oxygen is
$:\left(\right.$ Given : Molar mass in gmol $\left.^{-1} \mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16\right)$
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