Let $C(\alpha, \beta)$ be the circumcenter of the triangle formed by the lines
$$
\begin{aligned}
& 4 x+3 y=69 \\
& 4 y-3 x=17 \text { and } \\
& x+7 y=61
\end{aligned}
$$
Then $(\alpha-\beta)^2+\alpha+\beta$ is equal to
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