The equation of a circle |Units and Measurements|JEEMAIN2023

JEE MAIN_2023

S2_290123

Question

The equation of a circle is given by $x^2+y^2=a^2$, where $a$ is the radius. If the equation is modified to change the origin other than $(0,0)$, then find out the correct dimensions of A and B in a new equation i $(x-A t)+\left(y-\frac{t}{B}\right)^2=a^2$. The dimensions oft is given as $\left[T^{-1}\right]$.

Select the correct option:

$A=\left[L^{-1} T\right], B=\left[L T^{-1}\right]$

$A=(L T], B=\left[L^{-1} T^{-1}\right]$

$A=\left[L^{-1} T^{-1}\right], B=\left[L T^{-1}\right]$

$A=\left[L^{-1} T^{-1}\right], B=[L T]$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution