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JEE MAIN 2023
13-4-23 S2
Question
$\mathrm{A}(\mathrm{g}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})+\mathrm{C}(\mathrm{g})$ is a first order reaction. The initial pressure of the system was found to be 800 mm Hg which increased to 1600 mm Hg after 10 min . The total pressure of the system after 30 min will be $\_\_\_\_$ mm Hg. (Nearest integer)
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Solution
Sol. $\quad t_{1 / 2}=10$ minutes $$ \begin{aligned} & \left(P_A\right)_{30 \text { min. }}=\left(P_A\right)_0\left(\frac{1}{2}\right)^{30 / 10} \\ & \left(P_A\right)_{30 \text { min. }}=100 \mathrm{~mm} \mathrm{Hg} \\ & \begin{array}{c} \text { at } t=0 \quad \begin{array}{c} A(g) \\ 800 \mathrm{~mm} \end{array} \rightarrow \begin{array}{c} 2 B(g)_{n \sim}+C(g) \\ 0 \end{array} \\ \text { at } t=30 \quad 100 \mathrm{~mm} \quad 1400 \mathrm{~mm} \quad 700 \mathrm{~mm} \end{array} \end{aligned} $$ Total pressure after 30 minutes $=2200 \mathrm{~mm} \mathrm{Hg}$
Question Tags
JEE Main
Chemistry
Medium
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