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JEE MAIN 2025
4-4-2025 S2
Question
The centre of a circle $C$ is at the centre of the ellipse $E: \frac{x^2}{a^2}+\frac{y^2}{b^2}=1, a>b$. Let $C$ pass through the foci $F_1$ and $F_2$ of $E$ such that the circle $C$ and the ellipse $E$ intersect at four points. Let $P$ be one of these four points. If the area of the triangle $P F_1 F_2$ is 30 and the length of the major axis of $E$ is 17 , then the distance between the foci of $E$ is :
Select the correct option:
A
26
B
12
C
13/2
D
13
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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