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JEE MAIN 2022
{S1}_29.06.22
Question
A body is performing simple harmonic with an amplitude of 10 cm . The velocity of the body was tripled by air Jet when it is at 5 cm from its mean position. The new amplitude of vibration is $\sqrt{\mathrm{x}} \mathrm{cm}$. The value of x is $\_\_\_\_$
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Question Tags
JEE Main
Physics
Medium
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