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JEE MAIN 2022
29-06-2022 S2
Question
Spin only magnetic moment of $[\mathrm{MnBr} \mathbf{r}]^{4-}$ is $\_\_\_\_$ B.M. (round off to the closest integer)
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Solution
$\begin{aligned} & \mathrm{Mn}^{2+} \rightarrow \mathrm{t}_{2 \mathrm{~g}^{111}} \mathrm{e}_{\mathrm{g}^{11}} \\ & \mu_{\mathrm{s}}=\sqrt{35} \\ & =5.91=6\end{aligned}$
Question Tags
JEE Main
Chemistry
Easy
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