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JEE MAIN 2021
26-02-2021 S1
Question
3.12 g of oxygen is adsorbed on 1.2 g of platinum metal. The volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 300 K in L is $\_\_\_\_$ . $$ \left[\mathrm{R}=0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right] $$
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Solution
$$ \mathrm{V}=\frac{\frac{3.12}{32} \times 0.0821 \times 300}{1}=2.40 \mathrm{l} $$ $\because 1.2 \mathrm{gm}$ adsorbs 2.40 l $\therefore 1 \mathrm{gm}$ adsorbs 2 l
Question Tags
JEE Main
Chemistry
Easy
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