The unit cell of copper corresponds... | Solid State JEE Main 2021

JEE MAIN 2021

25-02-2021 S2

Question

The unit cell of copper corresponds to a face centered cube of edge length $3.596 A $ with one copper atom at each lattice point. The calculated density of copper in $\mathrm{kg} / \mathrm{m}^3$ is $\_\_\_\_$ [Molar mass of $\mathrm{Cu}: 63.54 \mathrm{~g} ;$ Avogadro Number $\left.=6.022 \times 10^{23}\right]$

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Solution

$$ \begin{aligned} &\text { FCC, }\\ &\begin{aligned} & d=\frac{Z \times M}{N_A \times a^3}=\frac{4 \times 63.54}{1000 \times 6.022 \times 10^{23} \times\left(3.596 \times 10^{-10}\right)^3} \\ & =9076 \mathrm{~kg} / \mathrm{m}^3 \end{aligned} \end{aligned} $$

Question Tags

JEE Main

Chemistry

Easy

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