For a reaction scheme formation |ChemicalKineticJEEMain2019

JEE MAIN 2019

08-04-2019 S2

Question

For a reaction scheme $A \xrightarrow{k_1} B \xrightarrow{k_2} C$, if the rate of formation of $B$ is set to be zero then the concentration of B is given by:

Select the correct option:

$\mathrm{k}_1 \mathrm{k}_2[\mathrm{~A}]$

$\left(\mathrm{k}_1-\mathrm{k}_2\right)[\mathrm{A}]$

$\left(\frac{\mathrm{k}_1}{\mathrm{k}_2}\right)[\mathrm{A}]$

$\left(k_1+k_2\right)[A]$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & A \xrightarrow{k_1} B \xrightarrow{k_2} C \\ & \frac{d[B]}{d t}=k_1[A]-k_2[B]=0 \\ & {[B]=\frac{k_1[A]}{k_2}}\end{aligned}$

Question Tags

JEE Main

Chemistry

Easy

Start Preparing for JEE with Competishun

Report Issue