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JEE-MAIN 2021
01-09-2021 S2
Question
The number of atoms in 8 g of sodium is $x \times 10^{23}$. The value of x is________.(Nearest integer)
[Given: $\mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23} \mathrm{~mol}^{-1}$ Atomic mass of $\mathrm{Na}=23.0 \mathrm{u}$ ]
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JEE Main
Chemistry
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