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JEE MAIN 2021
27-08-21 S1
Question
1 kg of 0.75 molal aqueous solution of sucrose can be cooled up to $-4^{\circ} \mathrm{C}$ before freezing. The amount of ice (in g ) that will be separated out is $\_\_\_\_$ (Nearest integer)
[Given : $\left.\mathrm{Kt}_{\mathrm{f}}\left(\mathrm{H}_2 \mathrm{O}\right)=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right]$
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Question Tags
JEE Main
Chemistry
Hard
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