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JEE-MAIN 2021
26-08-2021 S2
Question
For the galvanic cell
$$ \mathrm{Zn}(\mathrm{~s})+\mathrm{Cu}^{2+}(0.02 \mathrm{M}) \rightarrow \mathrm{Zn}^{2+}(0.04 \mathrm{M})+\mathrm{Cu}(\mathrm{~s}) $$ $\mathrm{E}_{\text {cell }}=$ $\_\_\_\_$ $\times 10^{-2} \mathrm{~V}$. (Nearest integer) $$ \left[\text { Use }: \mathrm{E}_{\mathrm{Cu}^{\circ} \mathrm{Cu}^{2^{+}}}^0=-0.34 \mathrm{~V}, \mathrm{E}_{\mathrm{Zn}^{\prime} / \mathrm{Zn}^{2^{+}}}^0=+0.76 \mathrm{~V}, \frac{2.303 \mathrm{RT}}{\mathrm{~F}}=0.059 \mathrm{~V}\right] $$
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JEE Main
Physics
Easy
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