100 mL of $\mathrm{Na}_3 \mathrm{PO}_4$ solution contains 3.45 g of sodium. The molarity of the solution is $\_\_\_\_$ $\times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$. (Nearest integer) [Atomic Masses - Na : 23.0 u, O : 16.0 u, $\mathrm{P}: 31.0 \mathrm{u}] \mid$
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