One mole of an ideal gas|KTG & THERMODYNAMICS|JEE-Main 2019

JEE MAIN 2019

10-04-2019 S2

Question

One mole of an ideal gas passes through a process where pressure and volume obey the relation $\mathrm{P}=\mathrm{P}_0\left[1-\frac{1}{2}\left(\frac{\mathrm{v}_0}{\mathrm{v}}\right)^2\right]$. Here $\mathrm{P}_0$ and $\mathrm{V}_0$ are constants. Calculate the change in the temperature of the gas if its volume changes from $V_0$ to $2 V_0$.

Select the correct option:

$\frac{1}{4} \frac{P_0 V_0}{R}$

$\frac{5}{4} \frac{\mathrm{P}_0 \mathrm{~V}_0}{\mathrm{R}}$

$\frac{1}{2} \frac{P_0 V_0}{R}$

$\frac{3}{1} \frac{P_0 V_0}{D}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution