Report Issue

JEE MAIN 2020
09-01-20 S1
Question
Consider a sphere of radius $R$ which carries a uniform charge density $\rho$. If a sphere of radius $\frac{R}{2} \frac{R}{2}$ is carved out of it, as shown, the ratio $\frac{\left|\vec{E}_A\right|}{\left|\vec{E}_B\right|}$ of magnitude of electric field $\overrightarrow{\mathrm{E}}_A$ and $\overrightarrow{\mathrm{E}}_B$, respectively, at points $A$ and $B$ due to the remaining portion is:
Question Image
Select the correct option:
A
$\frac{18}{34}$
B
$\frac{18}{54}$
C
$\frac{21}{34}$
D
$\frac{17}{54}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Physics
Hard
Start Preparing for JEE with Competishun