The volume (in mL ) of $0.125 \mathrm{M} \mathrm{AgNO}_3$ required to quantitatively precipitate chloride ions in 0.3 g of $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3$ is $\_\_\_\_$ .
$\mathrm{M}\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3=267.46 \mathrm{~g} / \mathrm{mol}$
$\mathrm{MAgNO}_3=169.87 \mathrm{~g} / \mathrm{mol}$