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JEE MAIN_2019_
S1_100419
Question
In a photoelectric effect experiment the threshold wavelength of light is 380 nm . If the wavelength of incident light is 260 nm , the maximum kinetic energy of emitted electrons will be , Given $E($ in eV$)=\frac{1237}{\lambda(\text { in } \mathrm{nm})}$
Select the correct option:
A
4.5 eV
B
15.1 eV
C
3.0 eV
D
1.5 eV
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Solution
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Question Tags
JEE Main
Physics
Easy
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