Let A₁ be the bounded area enclosed... | Area Under Curves

JEE MAIN 2026

24-01-2026 S1

Question

Let $\mathrm{A}_1$ be the bounded area enclosed by the curves $y=x^2+2, x+y=8$ and $y$-axis that lies in the first quadrant. Let $\mathrm{A}_2$ be the bounded area enclosed by the curves $y=x^2+2, y^2=x, x=2$, and $y$ axis that lies in the first quadrant. Then $\mathrm{A}_1-\mathrm{A}_2$ is equal to

Select the correct option:

$\frac{2}{3}(2 \sqrt{2}+1)$

$\frac{2}{3}(4 \sqrt{2}+1)$

$\frac{2}{3}(\sqrt{2}+1)$

$\frac{2}{3}(3 \sqrt{2}+1)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution