If the solution curve $y=f(x)$ of the differential equation
$$
\left(x^2-4\right) y^{\prime}-2 x y+2 x\left(4-x^2\right)^2=0, x>2,
$$
passes through the point $(3,15)$, then the local maximum value of $f$ is $\_\_\_\_$ .
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
