Chemical Equilibrium JEE Main | Degree of Dissociatio n

JEE MAIN 2025

23-01-2025 SHIFT-2

Question

Consider the reaction $\mathrm{X}_{2} \mathrm{Y}(\mathrm{g}) \rightleftharpoons \mathrm{X}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{Y}_{2}(\mathrm{~g})$. The equation representing correct relationship between the degree of dissociation $(x)$ of $X_{2} Y(g)$ with its equilibrium constant Kp is $\_\_\_\_$ . Assume x to be very very small.

Select the correct option:

$x=\sqrt[3]{\frac{2 K p}{p}}$

$x=\sqrt[3]{\frac{K p}{2 p}}$

$x=\sqrt[3]{\frac{K p}{p}}$

$x=\sqrt[3]{\frac{2 \mathrm{Kp}^{2}}{\mathrm{p}}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution