If ${_0}$ denotes the permittivity of free space and ${\Phi _E}$ is the flux of the electric field through the area bounded by the closed surface, then dimensions of $\left(\epsilon_0 \frac{d \phi_E}{d t}\right)$ are that of :
Select the correct option:
A
electric charge
B
electric current
C
electric potential
D
electric field
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
We know that formula for displacement current is given by
$\left(\epsilon_0 \frac{d \phi_E}{d t}\right)$
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