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JEE Advance 2021
Paper-2
Multiple correct answers - Select all that apply
Question
For a prism of prism angle $\theta=60^{\circ}$, the refractive indices of the left half and the right half are, respectively, and ( $n_2 \geq n_1$ ) as shown in the figure. The angle of incidence $i$ is chosen such that the incident light rays will have minimum deviation if $=n=1.5$. For the case of unequal refractive indices, $n_1=n$ and $n_2=n+\Delta n$ (where $\Delta n \ll n$ ), the angle of emergence $e=i+\Delta e$. Which of the following statement(s) is (are) correct ?
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Select ALL correct options:
A
The value of $\Delta e$ (in radians) is greater than that of $\Delta n$
B
$\Delta \mathrm{e}$ is proportional to $\Delta \mathrm{n}$
C
$\Delta$e lies between 2.0 and 3.0 milliradians, if $\Delta n=2.8 \times 10^{-3}$
D
$\Delta$ e lies between 1.0 and 1.6 milliradians, if $\Delta n=2.8 \times 10^{-3}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
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Question Tags
JEE Advance
Physics
Easy
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