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JEE-ADVANCED-2014
PAPER 1
Question
Let $E_1(r), E_2(r)$ and $E_3(r)$ be the respective electric fields at a distance $r$ from a point charge $Q$, an infinitely long wire with constant linear charge density $\lambda$, and an infinite plane with uniform surface charge density $\sigma$. if $E_1\left(r_0\right)=E_2\left(r_0\right)=E_3\left(r_0\right)$ at a given distance $r_0$, then
Select the correct option:
A
$Q=4 \sigma \pi r_0^2$
B
$\mathrm{r}_0=\frac{\lambda}{2 \pi \sigma}$
C
$\mathrm{E}_1\left(\mathrm{r}_0 / 2\right)=2 \mathrm{E}_2\left(\mathrm{r}_0 / 2\right)$
D
$\mathrm{E}_2\left(\mathrm{r}_0 / 2\right)=4 \mathrm{E}_3\left(\mathrm{r}_0 / 2\right)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Advance
Physics
Easy
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