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JEE MAIN 2025
02-04-2025 SHIFT-2
Question
When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K ) and acidified with acetic acid, the mass $(\mathrm{g})$ of 0.1 mole of product formed is :
(Given molar mass in $\mathrm{gmol}^{-1} H: 1, C: 12, N: 14, O: 16, S: 32$ )
Select the correct option:
A
343
B
330
C
33
D
66
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Chemistry
Easy
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