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JEE MAIN 2022
29-06-2022 S2
Question
A box contains 0.90 g of liquid water in equilibrium with water yapour at $27^{\circ} \mathrm{C}$. The equilibrium vapour pressure of water at $27^{\circ} \mathrm{C} 32.0$ Torr. When the volume of the box is increased, some of the liquid water evaporates to maintain the equilibrium pressure. If all the liquid water evaporates, then the volume of the box must be $\_\_\_\_$ litre [nearest integer] (Given: $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ ) (Ignore the volume of the liquid water and assume water yapours behave as an ideal gas.)
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Solution
$V=\frac{n R T}{P}=\frac{0.90 \times 0.82 \times 300 \times 760}{18 \times 32}=29.21$
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