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JEE MAIN 2022

25-06-2022 S2

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A solution of $\mathrm{Fe}_2\left(\mathrm{SO}_4\right)_3$ is electrolyzed for ' x ' min with a current of 1.5 A to deposit 0.3482 g of Fe. The value of x is $\_\_\_\_$ . [nearest integer] Given : $1 \mathrm{~F}=96500 \mathrm{C} \mathrm{mol}^{-1}$ Atomic mass of $\mathrm{Fe}=56 \mathrm{~g} \mathrm{~mol}^{-1}$

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