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JEE MAIN 2019
11-01-2019 S1
Question
A square is inscribed in the circle $x^2+y^2-6 x+8 y-103=0$ with its sides parallel to the coordinate axes. Then the distance of the vertex of this square which is nearest to the origin is:
Select the correct option:
A
6
B
$\sqrt{41}$
C
13
D
$\sqrt{137}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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