Surface Chemistry_JEE-Main 2020_S1_8-1-20 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2020

08-01-20 S1

Question

As per Hardy-Schulze formulation, the flocculation values of the following for ferric hydroxide sol are in the order

Select the correct option:

$\mathrm{AlCl}_3>\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]>\mathrm{K}_2 \mathrm{CrO}_4>\mathrm{KBr}=\mathrm{KNO}_3$

$\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]<\mathrm{K}_2 \mathrm{CrO}_4<\mathrm{KBr}=\mathrm{KNO}_3=\mathrm{AlCl}_3$

$\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]>\mathrm{AlCl}_3>\mathrm{K}_2 \mathrm{CrO}_4>\mathrm{KBr}>\mathrm{KNO}_3$

$\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]<\mathrm{K}_2 \mathrm{CrO}_4<\mathrm{AlCl}_3<\mathrm{KBr}<\mathrm{KNO}_3$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Easy

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