Bleaching powder and bleach solution are produced on a large scale and used in several house hold products. The effectiveness of bleach solution is often measured by iodometry.
25 mL of household bleach solution was mixed with 30 mL of 0.50 M KI and 10 mL of 4 N acetic acid. In the titration of the liberated iodine, 48 mL of $0.25 \mathrm{~N} \mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3$ was used to reach the end point. The molarity of the household bleach solution is
Select the correct option:
A
0.48 M
B
0.96 M
C
0.24 M
D
0.024 M
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Solution
$\begin{aligned} \text { milli mole of Hypo } & =0.25 \times 48 \\ & =2 \times \text { milli mole of } \mathrm{Cl}_2\end{aligned}$
milli mole of $\mathrm{Cl}_2=\frac{0.25 \times 48}{2}=6$ milli mole
$$
\text { = milli mole of } \mathrm{Cl}_2=\text { milli mole of } \mathrm{CaOCl}_2
$$
So, molarity $=\frac{6}{25} \mathrm{M}=0.24 \mathrm{M}$
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