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JEE-MAIN 2020
03-09-2020 S2
Question
Complex A has a composition of $\mathrm{H}_{12} \mathrm{O}_6 \mathrm{Cl}_3 \mathrm{Cr}$. If the complex on treatment with conc. $\mathrm{H}_2 \mathrm{SO}_4$ loses $13.5 \%$ of its original mass, the correct molecular formula of A is [Given : atomic mass of $\mathrm{Cr}=52$ amu and $\mathrm{Cl}=35 \mathrm{amu}$ ]
Select the correct option:
A
$\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3$
B
$\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right) 4 \mathrm{Cl}_2\right] \mathrm{Cl} \cdot 2 \mathrm{H}_2 \mathrm{O}$
C
$\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_3 \mathrm{Cl}_3\right] \cdot 3 \mathrm{H}_2 \mathrm{O}$
D
$\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 \cdot \mathrm{H}_2 \mathrm{O}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Easy
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