Compound $\mathrm{A}, \mathrm{C}_5 \mathrm{H}_{10} \mathrm{O}_5$, given a tetraacetate with $\mathrm{Ac}_2 \mathrm{O}$ and oxidation of A with $\mathrm{Br}_2-\mathrm{H}_2 \mathrm{O}$ gives an acid, $\mathrm{C}_5 \mathrm{H}_{10} \mathrm{O}_6$. Reduction of A with HI gives isopentane. The possible structure of A is :
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