Consider the following pairs of electrons (A) (a) $\mathrm{n}=3, \ell=1, \mathrm{~m}_1=1, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$ (b) $\mathrm{n}=3, \ell=2, \mathrm{~m}_1=1, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$ (B) (a) $\mathrm{n}=3, \ell=2, \mathrm{~m}_1=-2, \mathrm{~m}_{\mathrm{s}}=-\frac{1}{2}$ (b) $\mathrm{n}=3, \ell=2, \mathrm{~m}_1=-1, \mathrm{~m}_{\mathrm{s}}=-\frac{1}{2}$ (C) (a) $\mathrm{n}=4, \ell=2, \mathrm{~m}_1=2, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$ (b) $\mathrm{n}=3, \ell=2, \mathrm{~m}_1=2, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$ The pairs of electron present in degenerate orbitals is/are: