Dimension of 1 divided by μ₀ε₀..... | JEE Main 2023

JEE MAIN 2023

08-04-23 S1

Question

Dimension of $\frac{1}{\mu_0 \epsilon_0}$ should be equal to

Select the correct option:

$\mathrm{T}^2 / \mathrm{L}^2$

L/T

$\mathrm{L}^2 / \mathrm{T}^2$

T/L

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\frac{1}{\mu_0 \epsilon_0}=c^2 \Rightarrow\left[\frac{1}{\mu_0 \epsilon_0}\right]=\left[c^2\right]=\left[L^2 T^{-2}\right]$

Question Tags

JEE Main

Physics

Easy

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