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JEE Advance 2008
paper 2
Question
Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of $\mathrm{H}_2$ gas at the cathode is ( 1 Faraday $=96,500 \mathrm{C} \mathrm{mol}^{-1}$ )
Select the correct option:
A
$9.6 \times 10^4 \mathrm{sec}$
B
$19.3 \times 10^4 \mathrm{sec}$
C
$28.95 \times 10^4 \mathrm{sec}$
D
$38.6 \times 10^4 \mathrm{sec}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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