For the given reactions
$\mathrm{Sn}^{2+}+2 \mathrm{e}-\rightarrow \mathrm{Sn}$
$\mathrm{Sn}^{4+}+4 \mathrm{e}-\rightarrow \mathrm{Sn}$
The electrode potentials are; $\mathrm{E}_{\mathrm{Sn}^{2+} / \mathrm{Sn}}^{\circ}=-0.140 \mathrm{~V}$ and $\mathrm{E}_{\mathrm{Sn}^{4+} / \mathrm{Sn}}^{\circ}=0.010 \mathrm{~V}$. The magnitude of standard electrode potential for $\mathrm{Sn}^{4+} / \mathrm{Sn}^{2+}$ i.e. $\mathrm{E}_{\mathrm{Sn}^{4+} / \mathrm{Sn}^{2+}}^{\circ}$ is $\_\_\_\_$ $\times 10^{-2} \mathrm{~V}$. (Nearest integer)
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇