In a line of sight radio communication, a distance of about 50 km is kept between the transmitting and receiving antennas. If the height of the receiving antenna is 70 m , then the minimum height of the transmitting antenna should be :
(Radius of the Earth $=6.4 \times 10^6 \mathrm{~m}$ ).
Select the correct option:
A
20 m
B
51 m
C
32 m
D
40 m
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$$
\sqrt{2 \times 70 \times \mathrm{R}_{\mathrm{E}}}+\sqrt{2 \times \mathrm{h}_{\mathrm{R}} \times \mathrm{R}_{\mathrm{E}}}=50 \times 10^3
$$
Putting $R_E=6.4 \times 10^6 \mathrm{~m}$ and solving we get $\quad h_R=32 \mathrm{~m}$
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