In a parallel plate capacitor set up, the plate area of capacitor is $2 \mathrm{~m}^2$ and the plates are separated by 1 m . If the space between the plates are filled with a dielectric material of thickness 0.5 m and area $2 \mathrm{~m}^2$ (see fig.) the capacitance of the set-up will be $\_\_\_\_$ $\varepsilon_0$. (Dielectric constant of the material $=3.2$ ) (Round off to the Nearest Integer)