Let $b_i>1$ for $i=1,2, \ldots, 101$. Suppose $\log _e b_1, \log _e b_2, \ldots, \log _e b_{101}$ are in Arithmetic Progression (A.P.) with the common difference $\log _e 2$. Suppose $a_1, a_2, \ldots ., a_{101}$ are in A.P. such that $a_1=b_1$ and $\mathrm{a}_{51}=\mathrm{b}_{51}$. If $\mathrm{t}=\mathrm{b}_1+\mathrm{b}_2+\ldots .+\mathrm{b}_{51}$ and $\mathrm{s}=\mathrm{a}_1+\mathrm{a}_2+\ldots .+\mathrm{a}_{51}$, then
Select the correct option:
A
$s>t$ and $a_{101}>b_{101}$
B
$\mathrm{s}>\mathrm{t}$ and $\mathrm{a}_{101}<\mathrm{b}_{101}$
C
$\mathrm{s}<\mathrm{t}$ and $\mathrm{a}_{101}>\mathrm{b}_{101}$
D
$\mathrm{s}<\mathrm{t}$ and $\mathrm{a}_{101}<\mathrm{b}_{101}$
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