If an alpha particle with.... | JEE Main 2026 21 Jan Shift 1

JEE MAIN 2026

21-01-2026 S1

Question

If an alpha particle with energy 7.7 MeV is bombarded on a thin gold foil, the closest distance from nucleus it can reach is $\_\_\_\_$ m. (Atomic number of gold $=79$ and $\frac{1}{4 \pi \epsilon_{\mathrm{o}}}=9 \times 10^9$ in SI units)

Select the correct option:

$2.95 \times 10^{-14}$

$2.95 \times 10^{-16}$

$3.85 \times 10^{-16}$

$3.85 \times 10^{-14}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

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JEE Main

Physics

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