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JEE MAIN 2021
31.08.21_S2
Question
The electric field in an electromagnetic wave is given by $\mathrm{E}=\left(50 \mathrm{NC}^{-1}\right) \sin \omega(\mathrm{t}-\mathrm{x} / \mathrm{c})$ The energy contained in a cylinder of volume V is $5.5 \times 10^{-12} \mathrm{~J}$. The value of V is $\_\_\_\_$ $\mathrm{cm}^3$. (given $\epsilon_0=8.8 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}$ )
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Question Tags
JEE Main
Physics
Medium
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