Parabola y²=4x Divides Circle x²+y².... | JEE Main 2024

JEE MAIN

09-04-24 S1

Question

The parabola $y^2=4 x$ divides the area of the circle $x^2+y^2=5$ in two parts. The area of the smaller part is equal to :

Select the correct option:

$\frac{2}{3}+5 \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$

$\frac{1}{3}+5 \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$

$\frac{1}{3}+\sqrt{5} \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$

$\frac{2}{3}+\sqrt{5} \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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