Two cells are connected in opposition as shown. Cell $E_1$ is of 8V emf and 2Ω internal resistance; the cell $E_2$ is of 2V emf and 4Ω internal resistance. The terminal potential difference of cell $E_2$ is:
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Solution
I=(8-2)/(2+4)=6/6=1A
Applying Kirchhoff from C to B
$\begin{aligned} & V_C-2-4 \times 1=V_B \\ & V_C-V_B=6 \mathrm{~V} \\ & =6 \mathrm{~V}\end{aligned}$
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I=(8-2)/(2+4)=6/6=1A