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JEE MAIN 2023
11-4-2023 S2
Question
What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg ? (Assume dilute solution is being formed) Given: Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is $180 \mathrm{~g} \mathrm{~mol}^{-1}$.
Select the correct option:
A
4.69 g
B
3.59 g
C
2.59 g
D
3.69 g
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Solution
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Question Tags
JEE Main
Physics
Medium
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