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JEE MAIN 2019
10-04-2019 S2
Question
1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 5. The ratio of the elevation in their boiling points, $\frac{\Delta T_b(A)}{\Delta T_b(B)}$, is
Select the correct option:
A
1 : 5
B
10 : 1
C
5 : 1
D
1 : 0.2
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & \Delta T_b=k_b \times m \\ & \therefore \quad \frac{\left(\Delta T_b\right)_A}{\left(\Delta T_b\right)_B}=\frac{\left(k_b\right)_A}{\left(k_b\right)_B}=\frac{1}{5}\end{aligned}$
Question Tags
JEE Main
Chemistry
Easy
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