The integral equals.......................

JEE MAIN 2019

11-01-2019 S2

Question

The integral $\int_{\pi / 6}^{\pi / 4} \frac{d x}{\sin 2 x\left(\tan ^5 \times \cot ^5 x\right)}$ equals :

Select the correct option:

$\frac{1}{10}\left(\frac{\pi}{4}-\tan ^{-1}\left(\frac{1}{9 \sqrt{3}}\right)\right)$

$\frac{1}{20} \tan ^{-1}\left(\frac{1}{9 \sqrt{3}}\right)$

$\frac{\pi}{40}$

$\frac{1}{5}\left(\frac{\pi}{4}-\tan ^{-1}\left(\frac{1}{3 \sqrt{3}}\right)\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Hard

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