$50 \mathrm{~W} / \mathrm{m}^2$ energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy ( $25 \%$ ) is reflected from the surface and the rest is absorbed. The force exerted on $1 \mathrm{~m}^2$ surface area will be close to
$\left(c=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right)$