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JEE MAIN 2019
09-04-2019 S2
Question
$50 \mathrm{~W} / \mathrm{m}^2$ energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy ( $25 \%$ ) is reflected from the surface and the rest is absorbed. The force exerted on $1 \mathrm{~m}^2$ surface area will be close to
$\left(c=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right)$
Select the correct option:
A
$20 \times 10^{-8} \mathrm{~N}$
B
$35 \times 10^{-8} \mathrm{~N}$
C
$15 \times 10^{-8} \mathrm{~N}$
D
$10 \times 10^{-8} \mathrm{~N}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Physics
Hard
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