50 mL of $0.1 \mathrm{M} \mathrm{CH}_3 \mathrm{COOH}$ is being titrated against 0.1 M NaOH . When 25 mL of NaOH has been added, the pH of the solution will be $\_\_\_\_$ $\times 10^{-2}$. (Nearest integer)
(Given : $\left.\mathrm{pKa}\left(\mathrm{CH}_3 \mathrm{COOH}\right)=4.76\right)$
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇