The number of neutrons present in the more abundant isotope of boron is ' $x$ '. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is ' $y$ '. The value of $x+y$ is $\ldots$
Select the correct option:
A
4
B
6
C
3
D
9
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
More abundant isotope $=\mathrm{B}^{11}$
[Number of neutrons = 6]
$$
\begin{aligned}
& x=6 \\
& B+O_2 \rightarrow B_2 O_3
\end{aligned}
$$
Oxidation state of B in $\mathrm{B}_2 \mathrm{O}_3=+3$
So, $y=3$
Hence $\mathrm{x}+\mathrm{y}=9$
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